Simplify ____ 3³ Öx 5 y 5 Prime factor what's under the cube root radical _____ 3³ Öx·x·x·x·x·y·y·y·y·y Since it's cube root (index 3), group like factors into groups of 3 each _____ 3³ Ö(x·x·x)·x·x·(y·y·y)·y·y Each group of three is a perfect cube, and so each comes out in front of the radical as a single factor That Simplify (x/3y/5)^3 (x/3y/5)^3 Solve the given pair of linear equations and find the value of x and z tex\sf{\longrightarrow\\dfrac{4}{16x24z Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange
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Simplify (x/3 y/5)^3-(x/3-y/5)^3
Simplify (x/3 y/5)^3-(x/3-y/5)^3-Question To simplify the expression into the form x^r*y^s we first rewrite each term in fractional powers {{ sqrt (x^2*y^2) = x^1*y^1 }}, {{ 3 sqrt (x^5*y^4) = x^(5/3)*y^(4/3) }} and {{ 5 sqrt (x^5) = x^1 }} Combining all the powers we get = x^__*y^__Simplify\\frac{6}{x1}\frac{3}{x1} simplify\\frac{5x}{6}\frac{3x}{2} simplifycalculator simplify x^{2} en Related Symbolab blog posts Middle School Math Solutions – Equation Calculator Welcome to our new "Getting Started" math solutions series Over the next few weeks, we'll be showing how Symbolab
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Simplify 1/(x^3y^5) Simplify the denominator Tap for more steps Rewrite the expression using the negative exponent rule Rewrite the expression using the negative exponent rule To write as a fraction with a common denominator, multiply by To write as a fraction with a common denominator, multiply byYou can put this solution on YOUR website!X = 158 y = 063 First, let me write what is given 2^x 3^y = 5 2^x2 3^y1 = 18 Which can be written as 2^x2^2 3^y3^1 = 18 42^x 33^y = 18 Now, let's assume 2^x =m 3^y=n So, when we replace the above, we get two equation
Answer to Simplify x(x^4 (x^3)^2)^5/3 Simplify (x^3 y^5/(x^5 y^2)^3) Get 11 help now from expert Precalculus tutors Solve it with our from expert Precalculus tutors Solve it with ourWrite each expression with a common denominator of x 2 y 4 x 2 y 4, by multiplying each by an appropriate factor of 1 1 Tap for more steps Multiply 1 x 2 1 x 2 and y 4 y 4 y 4 y 4 Multiply 1 y 4 1 y 4 and x 2 x 2 x 2 x 2 Reorder the factors of x 2 y 4 x 2 y 4 Combine the numerators over the common denominatorHow do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties?
If x^3 y^3 =3 , use only implicit diff to find d^2y/dx^2 Express your answer in terms of x and y only and write is as a proper fraction that is completely simplified as much as possible d^2y/dx^2= 6x/y^5 (this is the answer I should get but i don't know how to show steps for this question) 👍 👎 👁Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor(1) "^3" was replaced by "^(3)" Step 1 x 8 y (6) Simplify ——————— x 3 y 5 Dividing exponential expressions 11 x 8 divided by x 3 = x (8 3) = x 5 Dividing exponential expressions 12 y (6) divided by y 5 = y ((6) 5) = y (11) = 1 / y 11 Final result x 5 ——— y 11
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Making Equivalent Fractions 53 Rewrite the two fractions into equivalent fractions Two fractions are called equivalent if they have the same numeric value For example 1/2 and 2/4 are equivalent, y/ (y1)2 and (y2y)/ (y1)3 are equivalent as well To calculate equivalent fraction , multiply the Numerator of each fraction, by itsElementary Technical Mathematics Simplify ( 4 x − 3 y ) ( 5 x 2 y ) more_vert Simplify ( 4 x − 3 y ) ( 5 x 2 y ) Buy Find launch Elementary Technical Mathematics 12th Edition For the following scores, find the value of each expression X 3 2 4 2 a X b (X)2 c X 2 d (X 2) Essentials of Statistics for The Behavioral SciencesHow do you simplify the expression #\frac{a^5b^4}{a^3b^2}#?
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Expand the following (y x)^8 (y x)^8 = sum_(k=0)^8 binomial(8, k) y^(8 k) x^k = binomial(8, 0) y^8 x^0 binomial(8, 1) y^7 x^1 binomial(8, 2) y^6 x^2 x^3/y^5 x^3y^5 Anything to a negative exponent can be rewritten as one (1) over that term, with a positive exponent For example x^2 can be 1/x^2 So, let's use that concept for your question x^3 * y^5 x^3 * 1/y^5 x^3/1 * 1/y^5 x^3/y^5 How do you evaluate the expression #(2^2/3^3)^3#?
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Learn with Tiger how to do (x/3y/5)^3(x/3y/5)^3 fractions in a clear and easy way Equivalent Fractions,Least Common Denominator, Reducing (Simplifying) Fractions Tiger Algebra SolverSwap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 5x3=y − 5 x 3 = y Subtract 3 from both sides Subtract 3 from both sides 5x=y3 − 5 x = y − 3 Divide both sides by 5Simplify sqrt(2x 3 y 5) Step 1 Simplify the Integer part of the SQRT Factor 2 into its prime factors 2 = 2 Note that 2 is a prime number, it only has itself as a factor (that is on top of the trivial factor "1") To simplify a square root, we extract factors which are squares, ie, factors that are raised to an even exponent
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Then type x=3 Try it now 2x @ x=3 Clickable Demo Try entering 2x @ x=3 into the text box After you enter the expression, Algebra Calculator will evaluate 2x for x=3 2(3) = 6 More Examples Here are more examples of how to evaluate expressions in Algebra Calculator Feel free to try them now Evaluate 3xy for x=2, y=3 3xy @ x=2, y=3Answer to Expand the given logarithm and simplify log (1000 x^3 y^5) By signing up, you'll get thousands of stepbystep solutions to yourFirst, rewrite the expression as #12/9(x^8/x^3)(y^3/y^5) =># #(3 xx 4)/(3 xx 3)(x^8/x^3)(y^3/y^5) =># #(color(red)(cancel(color(black)(3))) xx 4)/(color(red
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